Print out a Drupal Commerce field only if it has a value

In Drupal Commerce, you can use the following to print out a field in your node.tpl.php file:

<?php
 print render($content['product:field_NAME']); 
?>

But how do you print a field only if it has content?

For a normal Drupal field you would use the following:

<?php
if (isset ($node->field_NAME)):
  print $node->field_NAME['und'][0]['safe_value'];
endif; 
?>

But that doesn't work with a Drupal commerce field. I would appreciate if someone could offer any pointers!

big_smile

Posted: Apr 5, 2012

Comments

Also interested, still

sammyfm on February 10, 2013

Also interested, still couldnt find any answer for this...

There's no Drupal Commerce field, only entity fields, which can be a node (a product display) or a commerce_product (the product itself). If you need to check a field from the node, check it from the node. If you need to check from the commerce_product, check from it.

<?php
// let's assume we are in the /node/123 path, where we see a product display node
$commerce_product = commerce_product_load($node->field_your_productreference_field[$node->language][0]['product_id']);

if(isset($commerce_product->field_some_useful_field[LANGUAGE_NONE][0]['value'])) {
  // use the render() here
}
?>